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Finite Math Formulas

\[x = \displaystyle \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] \[ \displaystyle \Pr\left( a \le X\le b \right) = \Pr\left( \frac{a-\mu}{\sigma} \le Z \le \frac{b-\mu}{\sigma} \right) \]
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Is finite math harder than calculus?

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