# Pre Calculus Homework Help

For you guys taking High School or Pre-Calculus classes we have a lot to offer. We know how challenging the transition from High School to College can be. There's no need to struggle with incomplete study material.

Having a well explained list of solved problems can improve your learning 100 percent. Regrettably, current textbooks come mostly with the solutions to the sample problems, but they don't show detailed solutions.

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## Pre Calculus Topics

This is a list of subjects you may be interested on

**Algebra**- Systems of Equations.
- Word problems.
- Factorization.
- Polynomials
- Quadratic Equations

**Geometry**- Triangles.
- Areas and Volumes.
- Circles.
- Lines
- Planes

**Trigonometry**- Circles.
- Sine, Cosine, Tangent, Cotangent, Secant, Cosecant.
- Pythagoras Theorem.
- De Moivre's Formula.
- etc....

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## Our **Specialties**

#### Algebra

There are many Algebra topics covered in a Pre Calculus class, such as Systems of Equations, Word problems, Factorization, Polynomials, Quadratic Equations.

#### Geometry

We can help you with your Geometry homework, involving Triangles, Areas and Volumes, Circles, Lines, Planes, etc.

#### Trigonometry

Are you stuck with a Trigonometry assignment? Are you lost with Circles or with trigonometric functions such as Sine, Cosine, Tangent, Cotangent, Secant and Co-secant? We can help with that!

#### Basic Calculus

You will need to have some idea of Calculus to work on your pre-calculus course. We can cover you!

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Aside from Pre Calculus, we can also help with Stats, Calculus, Linear Algebra, Quantitative Methods, Decision Analysis, you name it

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We feel how you feel when you have to deal with those hard Calculus problems. We can help with that extra edge that you need! We can provide you with step-by-step solutions. See some examples below:

**Problem 1.** Solve the following system of equations:

**Solution.** We have to find $x$ and $y$ in such a way that (1) and (2) are satisfied simultaneously. The method consists on *eliminating* one of the variables using both equation, multiplying them by the right constants. More precisely, if we multiply the first equation by 2 we obtain

and now we sum both equations (3) and (4) to get $11x=33$, which means that $x=3$. Now that we have $x$, we can find $y$ simply replacing any of the equations (1) or (2). We choose (1), so we get $9+2y=11$, which implies that $2y=2$, and then $y=1$. Summarizing

\[ x=3 \quad , \quad y=1 \]is the solution. $\Box$

**Problem 2.** Rationalize the denominator

**Solution.** We have the factor $\sqrt 3-\sqrt 2$ in the denominator, so we multiply both the numerator and denominator by
the conjugate $\sqrt 3+\sqrt 2$, to obtain:

This way, we have found an equivalent expression with no radicals at the denominator, i.e.

\[ \displaystyle \frac{\sqrt{2}}{\sqrt 3-\sqrt 2}=\sqrt 6-2 \]
but this last expression is *rationalized*. $\Box$